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4.The brakes applied to a car produce an acceleration of 6 m/s 2 in the opposite direction to the motion. If the car takes 3 s to stop after the application of brakes, calculate the distance it travels during this time.

Answer» ONG>ANSWER:

the answer is 27m

ANSWER

Given:

ACCERLERATION: a=−6 m/s2

Time t=3 s

Final VELOCITY, v=0 m/s

v=u+at

0=u−6×3

u=18 m/s

s=ut+1/2×at^2

s=18×3+1/2×(−6)×9

s=54-27

⇒s=27m



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