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4.The brakes applied to a car produce an acceleration of 6 m/s 2 in the opposite direction to the motion. If the car takes 3 s to stop after the application of brakes, calculate the distance it travels during this time. |
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Answer» ONG>ANSWER: the answer is 27m ANSWER Given: ACCERLERATION: a=−6 m/s2 Time t=3 s Final VELOCITY, v=0 m/s v=u+at 0=u−6×3 u=18 m/s s=ut+1/2×at^2 s=18×3+1/2×(−6)×9 s=54-27 ⇒s=27m |
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