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4. Solve XT 1)5.Solve (x + 1)(x + 2)(x + 3)(x + 4) = 120.VE |
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Answer» Step-by-step EXPLANATION: (x−1)(x−2)(x−3)(x−4)=120(x−1)(x−4)(x−2)(x−3)=0(x2−4x−x+5)(x2−3x−2x+5)=0x2−5x+4)(x2−5x+6)=0letx2−5x=y(y+4)(y+6)=0y2+6y+4y+24=0y(y+6)+4(y+6)=0(y+6)(y+4)=0ify+6=0x2−5x+6=0x2−3x−2x+6=0x(x−3)−2(x−3)=0(x−3)(x−2)=0ifx−3=0x=3x−2=0x=2ify+4=0x2−5x+4=0x2−4x−x+4=0x(x−4)−1(x−4)=0(x−4)(x−1)=0ifx−4=0x=4ifx−1=0x=1\begin{lgathered}(x - 1)(x - 2)(x - 3)(x - 4) = 120 \\ (x - 1)(x - 4)(x - 2)(x - 3) = 0 \\ ( {x}^{2} - 4x - x + 5)( {x}^{2} - 3x - 2x + 5) = 0 \\ {x}^{2} - 5x + 4)( {x}^{2} - 5x + 6) = 0 \\ let \: {x}^{2} - 5x = y \\ (y + 4)(y + 6) = 0 \\ {y}^{2} + 6y + 4y + 24 = 0 \\ y(y + 6) + 4(y + 6) = 0 \\ (y + 6)(y + 4) = 0 \\ ify + 6 = 0 \\ {x}^{2} - 5x + 6 = 0 \\ {x}^{2} - 3x - 2x + 6 = 0 \\ x(x - 3) - 2(x - 3) = 0 \\ (x - 3)(x - 2) = 0 \\ if \: x - 3 = 0 \\ x = 3 \\ x - 2 = 0 \\ x = 2 \\ if \: y + 4 = 0 \\ {x}^{2} - 5x + 4 = 0 \\ {x}^{2} - 4x - x + 4 = 0 \\ x(x - 4) - 1(x - 4) = 0 \\ (x - 4)(x - 1) = 0 \\ if \: x - 4 = 0 \\ x = 4 \\ if \: x - 1 = 0 \\ x = 1\end{lgathered} (x−1)(x−2)(x−3)(x−4)=120 (x−1)(x−4)(x−2)(x−3)=0 (x 2 −4x−x+5)(x 2 −3x−2x+5)=0 x 2 −5x+4)(x 2 −5x+6)=0 letx 2 −5x=y (y+4)(y+6)=0 y 2 +6y+4y+24=0 y(y+6)+4(y+6)=0 (y+6)(y+4)=0 ify+6=0 x 2 −5x+6=0 x 2 −3x−2x+6=0 x(x−3)−2(x−3)=0 (x−3)(x−2)=0 ifx−3=0 x=3 x−2=0 x=2 ify+4=0 x 2 −5x+4=0 x 2 −4x−x+4=0 x(x−4)−1(x−4)=0 (x−4)(x−1)=0 ifx−4=0 x=4 ifx−1=0 x=1
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