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4.In the figure. O is the centre of the circleSeg AB is the chord and seg OP. chordAB. IF (AP) - 3x and (PB)-27thenfind the value of x |
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Answer» Answer: GIVEN, O is the center of a circle. AB=AC OP⊥AB OQ⊥AC ∠PBA=30 ∘
To prove :- BP∥QC Construction : Join BC, OC and OB. Proof : AB = AC ∠ACB=∠ABC __ (1) OC=OB [∵ radius] ∠OCB=∠OBC __ (2) ∴∠ACB=∠OBC=∠ABC−∠OBC [ using (1) - (2)] ⇒∠ACO=∠ABO __ (3) In △OXC and △OYB ∠OXC=∠OYB[∵OQ⊥AC&OP⊥AB] ∠AOC=∠ABO [using (3)] OC=OB ∴△OXC=≅△OYB [AAS] ∠QOC=∠POB [CPCT] __ (4) ∴ we PROVED that segPB∥segQC. Now in △QOC and △POB OQ=OB[∵ radius] ∠QOC=∠POB (using (4)) OC=OP(∵ radius) ∴△QOC≅△POB [SAS] ∴OQC=∠OBP [CPCT] ∴QC=BP Step-by-step explanation: https://haygot.s3.amazonaws.com/questions/1192133_1249612_ans_6d6e56b6000348ed8606c43ac94f5049.png |
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