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4. In Fig. 10.38, LABC 69, LACB 31. findZBDC |
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Answer» In ∆ ABC ∠ABC + ∠BAC + ∠ACB = 180°∠BAC = 180° - 31° - 69° = 80°BC is same base to ∆ ABC and ∆BDCSo, ∠BAC = ∠BDCTherefore ∠BAC = 80° |
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