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4. If the volume of a right circular cone of height 9 cm is 48 T cm", find the diameter of itsbase.​

Answer»

Let R be the radius of the cone.

= > volume = \frac{1}{3}\pi \: {r}^{2} h

= > 48 = \frac{1}{3} \times 3.14 \times {r}^{2} \times 9

= > {r}^{2} = \frac{48 \times 3}{3.14 \times 9} = \frac{144}{28.26} = 5.48

= > r = 2.34cm

DIAMETER = 2R = 4.68cm

Hence, diameter of the right circular cone is 4.68cm.

Hope this ANSWER helps you ^_^ !


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