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4. Find the total capacitance for three capacitors connected in series, giventheir individual capacitances are 10, 50, and 80 uF. |
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Answer» Let, C1 = 10 uf, C2= 50 uf, C3= 80 uf Total Capacitance when connected in series = 1/C1 + 1/C2 + 1/C3 = 1/10 + 1/50 + 1/80 = (40+8+5)/400 = 53/400 uf |
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