1.

4. Find the total capacitance for three capacitors connected in series, giventheir individual capacitances are 10, 50, and 80 uF.​

Answer»

ANSWER:

Let,

C1 = 10 uf, C2= 50 uf, C3= 80 uf

Total Capacitance when connected in series

= 1/C1 + 1/C2 + 1/C3

= 1/10 + 1/50 + 1/80

= (40+8+5)/400

= 53/400 uf



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