4. At 25 °C a 0.1 molal solution of CH3COOH is 1.35 % dissociated in an aqueoussolution. Calculate freezing point andosmotic pressure of the solution assumingmolality and molarity to be identical.

4. At 25 °C a 0.1 molal solution of CH3COOH is 1.35 % dissociated i

1.	4. At 25 °C a 0.1 molal solution of CH3COOH is 1.35 % dissociated in an aqueoussolution. Calculate freezing point andosmotic pressure of the solution assumingmolality and molarity to be identical.
Answer» Molality =0.1 mDegree of DISSOCIATION of CH3COOH=1.35%CH3COOH⇋ CH3COO−+H+ ; α%=1.35%100 0 0100−1.35 1.35 1.35∴i=100100−1.35+2×1.35 =100101.35=1.0135∴ΔTf=1.0135×1.86×0.1=0.1885∴Tfsolution=−0.1885oCπ=iCRT=1.0135×0.1×0.0821×298=2.48 ATMIF no dissociation is assumed i=1∴ Both △Tf & π are little bit HIGHER if i=1.0135 is considered