4 A train starting from rest attains a velocity of 108km/h in 10 minutes. Calculate (1) acceleration distance covered by the train.

4 A train starting from rest attains a velocity of 108km/h in 10 minut

1.	4 A train starting from rest attains a velocity of 108km/h in 10 minutes. Calculate (1) acceleration distance covered by the train.
Answer» -A train starting from rest attains a velocity of 108km/h in 10 minutes.To Find :-AccelerationDistanceSolution :-We KNOW THAT1 km/h = 5/18 m/s108 km/h = 108 × 5/18108 km/h = 6 × 5108 km/h = 30 m/s1 min = 60 sec10 min = 10 × 6010 min = 600 secNowa = (v - U)/ta = (30 - 0)/600a = 30/600a = 1/20a = 0.05 m/s²Nowv² - u² = 2AS(30)² - (0)² = 2(0.05)(s)900 - 0 = 0.1s900 = 0.1s900/0.1 = s9000/1 = s9000 = s

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4 A train starting from rest attains a velocity of 108km/h in 10 minutes. Calculate (1) acceleration distance covered by the train. ​

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4 A train starting from rest attains a velocity of 108km/h in 10 minutes. Calculate (1) acceleration distance covered by the train.