Given :- A thief saw a policeman from distance of 700m and started running. Thief could run 4.7km in 41 minutes & policeman can run the same distance in 34 minutes. Find the distance thief had run before being CAUGHT.

Solution :-

→ Thief runs = 4.7 km = 4.7 * 1000 = 4700 m.

→ Time taken = 41 min. =

→ speed of thief = (Distance/time) = (4700/41) m / min.

similarly,

→ Policeman runs = 4.7 km = 4.7 * 1000 = 4700 m.

→ Time taken = 34 min.

→ speed of Policeman = (Distance/time) = (4700/34) m / min.

then,

→ usual speed in same direction = speed of Policeman - speed of thief = (4700/34) - (4700/41) ={4700(41 - 34)} /34*41 = (4700 * 7)/1394 = 23.6 m/min.

therefore,

→ Time taken by policeman to CATCH the thief = (Distance between them) / usual speed = (700/23.6) = 29.67 minutes.

hence,

→ Distance covered by thief before caught = speed * time = (4700/41) * 29.67 ≈ 3401 m = 3.4 km (Ans.)

∴ The distance thief had run before being caught is 3.4 km .

Learn more :-

A leak in the body of a ship which can admit 5 units of water in 16 minutes got detected when it is 40km

away from the s...

brainly.in/question/26688438

A train starting from a station X was to arrive at a station Y at 6:06 PM. It could TRAVEL at 62.5% of its usual

speed a...

brainly.in/question/26746228