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4, A cylinder is open at one end. The external diameter is 15 cm and its thickness is 3 cm. If the height ofthe cylinder is 11 cm and if 1 cm weighs 9 gm, find:(i) The capacity of the cylinder(ii) Weight of the metal used in the cylinder. (π = 3.14) |
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Answer» Cylinder volume with external Diameter of 15 cm with height of 11 cm V₁ = πd²h/4 = π x 15² x 11 / 4 = 2475π/4 cm³ Cylinder volume of internal empty space with diameter of 9 cm (2 x 3 mm of thickness reduced) with height of 8 cm (3 cm thickness at bottom reduced and top is open) V₂=πd²h/4 = π x 9² x 8/4 = 648π/4 cm³ Effective volume of Cylinder material = V₁ - V₂ ⇒ (2475-648)π/4 = 1827π/4 = 1827 x (22/7) / 4 ⇒ 261 x 22/4 = 261 x 11/2 = 2871/2 = 1435.5 cm³ 1 cm³ weighs = 9 gm 1435.5 cm³ weighs = 1435.5 x 9 = 12,919.5 gms |
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