4. A block of mass 5 kg initially at rest at theorigin is acted upon by a force along thepositive X - direction represented byF=(20 +5x)N. Calculate the work done by theforce during the displacement of the blockfrom x=0 to x=4m.

4. A block of mass 5 kg initially at rest at theorigin is acted upon

1.	4. A block of mass 5 kg initially at rest at theorigin is acted upon by a force along thepositive X - direction represented byF=(20 +5x)N. Calculate the work done by theforce during the displacement of the blockfrom x=0 to x=4m.
Answer» 120 jouleExplanation:we KNOW smaller work DONE,DW=F.dsas force and displacement are in same direction so angle is 0 degree now dw= integration of Fds from x=0 to x=4we get w= (20x+5xsquare/2) from x=0 to x=4substituting value of x we get , W= 120 JOULE

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4. A block of mass 5 kg initially at rest at theorigin is acted upon by a force along thepositive X - direction represented byF=(20 +5x)N. Calculate the work done by theforce during the displacement of the blockfrom x=0 to x=4m.​

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4. A block of mass 5 kg initially at rest at theorigin is acted upon by a force along thepositive X - direction represented byF=(20 +5x)N. Calculate the work done by theforce during the displacement of the blockfrom x=0 to x=4m.