4A72 + B85C + 92D6 = E7775

Let's write them decimally.

Means writing the number in the form of 10x + y as x / y. (Not dividing)

Here, 4A72 = 4 / A / 7 / 2

B85C = B / 8 / 5 / C

92D6 = 9 / 2 / D / 6

E7775 = E / 7 / 7 / 7 / 5

4 / A / 7 / 2 + B / 8 / 5 / C + 9 / 2 / D / 6 = E / 7 / 7 / 7 / 5

= 4 + B + 9 / A + 8 + 2 / 7 + 5 + D / 2 + C + 6 = E / 7 / 7 / 7 / 5

= B + 13 / A + 10 / D + 12 / C + 8 = E / 7 / 7 / 7 / 5

The ones DIGIT of C + 8 is 5.

∴ C + 8 = 15

C = 15 - 8 = 7

∴ E / 7 / 7 / 7 / 5 = E / 7 / 7 / 6 / 15

The ones digit of D + 12 is 6.

∴ D + 12 = 16

D = 16 - 12 = 4

∴ E / 7 / 7 / 7 / 5 = E / 7 / 6 / 16 / 15

The ones digit of A + 10 is 6.

∴ A + 10 = 16

A = 16 - 10 = 6

∴ E / 7 / 7 / 7 / 5 = E / 6 / 16 / 16 / 15

Here, B + 13 = E / 6

∴ B + 13 = E / 6 = 16

B = 16 - 13 = 3

E / 6 = 16

∴ E = 1

A = 6; B = 3; C = 7; D = 4; E = 1

And the question given is actually,

4672 + 3857 + 9246 = 17775

Hope this may be helpful.

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