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(४ - 99) में #* का गुर्णक(8) - 2500(D) 99 x 50 |
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Answer» There are 50 brackets. So for making x^49, we will multiply x 49 times and mutiply the constant term 1 time. Since the no. of possible constant terms which may be taken are 50 Sn=(-1–3–5….-99)x^49 =50*100/2(-1)x^49 = -2500x^ 49 Coefficient of x^49= -2500option b |
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