4.9 grams of HSO, is present is 100 ml of the solution, then its molarity and normality are Alto Boteronta con

4.9 grams of HSO, is present is 100 ml of the solution, then its molar

1.	4.9 grams of HSO, is present is 100 ml of the solution, then its molarity and normality are Alto Boteronta con
Answer» H (g/L) of H2SO4 = 4.9100 × 1000 = 49 MOLARITY = StrengthMol. MASS = 4948 = 0.5 M Normality = N × Molarity n = Mol. massEq. mass = 9849 = 2 Normality ... Moreplease follow me