4 * ८०5 (4 + 2) - 2008 4+ ००8 दर को कथा 3. – InterviewSolution

1.

4 * ८०5 (4 + 2) - 2008 4+ ००8 दर को कथा 3.

Answer»

sin(A-B) - 2 sin A + sin(A - B)/cos(A + B) - 2 cos A + cos (A-B)

= 2sinA cosB - 2sin A/ 2cosA cos B - 2cos A

= 2sin A(cosB - 1)/ 2cos A(cos B - 1

= tan A

Hence proved

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