1.

4/5,a,6/5 are three consecutive terms of ap,then value of a is

Answer»

Answer:

1

Step-by-step explanation:

can be found by arithmetic mean....

LET the 1st term be B second term be A and third term be C

1) difference between FIRST two terms is of d = A-B

2) difference between the 2ND and 3rd term is d = C-A

3) equating both the EQUATIONS we get

A-B = C-A

as we know value of both B and C

B = 4/5

C= 6/5

then 2A = 4/5 + 6/5

2A = 10/5

2A = 2

therefore A = 1


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