1.

3x=y+5 and 5x-5y=11 by elimination method

Answer»

Step-by-step explanation:

above eqn can be written as

3x-y=5 ....(1)

5x-5y=11 ....(2)

multiplying by 5 in eqn (1) we get

15x-5y=25

5x-5y=11

after SUBTRACTING we get

10x=14

:::X=7/5

after putting the value of x in eqn (2) we get

7-5y=11

5y= -4

y= -4/5



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