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3x=y+5 and 5x-5y=11 by elimination method |
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Answer» Step-by-step explanation: above eqn can be written as 5x-5y=11 ....(2) multiplying by 5 in eqn (1) we get 15x-5y=25 5x-5y=11 after SUBTRACTING we get 10x=14 :::X=7/5 after putting the value of x in eqn (2) we get 7-5y=11 5y= -4 y= -4/5 |
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