1.

3x-5y=-1 and x-y=-1 by cross multiplication method

Answer»

[3x - 5Y = -1] × 1
[ x - y = -1] × 3

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3x - 5y = -1
3x - 3y = -3
-__(+)__(+)

0-2y = 2
________

=> 2y = -2

=> y = -2/2

=> y = -1


Putting the VALUE of y in x-y = -1

=> x -(-1) = -1

=> x+ 1 = -1

=> x = -1-1

=> x = -2

x = -2
y = -1




I hope this will help you


-by ABHAY


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