1.

3x+4y=25, 5x-6y=9 solve by substitute methode​

Answer»

Step-by-step explanation:

Given -

3x + 4y = 25

5x - 6y = 9

To Find -

VALUE of x and y by substitution method.

Now,

= 3x + 4y = 25

= 3x = 25 - 4y

  • = x = 25 - 4y/3

Substituting the value of x on

5x - 6y = 9

= 5(25 - 4y/3) - 6y = 9

= 125 - 20y/3 - 6y = 9

= 125 - 20y - 18y/3 = 9

= 125 - 38y/3 = 9

= 125 - 38y = 27

= 125 - 27 = 38y

= 98 = 38y

= y = 98/38

  • = y = 49/19

Now,

Substituting the value of y on

3x + 4y =25

= 3x + 4(49/19) = 25

= 3x + 196/19 = 25

= 57x + 196/19 = 25

= 57x + 196 = 25 × 19

= 57x + 196 = 475

= 57x = 475 - 196

= 57x = 279

= x = 279/57

= x = 93/19

Hence,

The value of x is 93/19

and

The value of y is 49/19

Verification -

Substituting the value of x and y on 3x + 4y = 25

= 3(93/19) + 4(49/19) = 25

= 279/19 + 196/19 = 25

= 279 + 196/19 = 25

= 475/19 = 25

= 25 = 25

LHS = RHS

Hence,

VERIFIED..


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