1.

3x+27/2+3x+9+45/2 find the value of x

Answer»

\huge\mathtt\colorbox{purple}{{\color{white}{answer~~~↓}}}

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\huge\bf{To~find~:}

The VALUE of ‛x’ in the EQUATION :

\large\sf{~~~~3x+{\frac{27}{2}}+3x+9+{\frac{45}{2}}}

\large\sf{→(3x+3x)+({\frac{27}{2}}+{\frac{45}{2}})+9}

\large\sf{→9x+{\frac{72}{2}}+9}

\large\sf{→9x+{\frac{72+18}{2}}}

\large\sf{→9x+{\frac{90}{2}}}

\large\sf{→9x+45}

\large\sf{→9x=-45}

\large\sf{→x={\frac{-45}{9}}}

\large\sf{→x={\underline{\underline{-5}}}}

\small{ }

\huge\bold\purple{Hope~it~helps..!!}



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