1.

√3x^2+2√2x-2√3=0 by discriminant​

Answer»

AnsWer :

32.

SolutioN :

We have, EQUATION.

\tt \dagger  \:  \:  \:  \:  \:  \sqrt{3} {x}^{2}   + 2 \sqrt{2} x - 2 \sqrt{3}  = 0.

# Compare with General Equation.

\tt \dagger \:  \:  \:  \:  \: a {x}^{2}  + bx + c = 0.

Where as,

  • a = √3.
  • b = 2√2.
  • c = - 2√3.

Now,

  • D ( Discriminant )

\tt \dagger \:  \:  \:  \:  \: D =  {b}^{2}  - 4ac.

\tt :  \implies D =  { \big(2 \sqrt{2} \big) }^{2}  - 4  \times  \sqrt{ 3} \times  - 2 \sqrt{3}  .

\tt :  \implies D =  8   +  24.

\tt :  \implies D = 32.

Therefore, the value of discriminant is 32.

Some INFORMATION :

† Condition 1.

† Condition 2.

  • D < 0.
  • Roots are unreal.

† Condition 3.

  • D = 0.
  • Both Roots are equal.


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