3x(1-x^2)dy/dx+(2x^2-1)y^3=ax^3

1.	3x(1-x^2)dy/dx+(2x^2-1)y^3=ax^3
Answer» Answer: have solved till dydx+(2x2−1)y33x(1−x2)y2=ax33x(1−x2)y2 y2dydx+(2x2−1)y33x(1−x2)=ax33x(1−x2) Substituting y3=t so the equation will be 13dtdx+(2x2−1)t3x(1−x2)=ax33x(1−x2) after this the INTEGRATING FACTOR is 1x1−x2−−−−−√ But I am unable to SOLVE it FORWARD.

Answer»

Answer:

have solved till

dydx+(2x2−1)y33x(1−x2)y2=ax33x(1−x2)y2

y2dydx+(2x2−1)y33x(1−x2)=ax33x(1−x2)

Substituting y3=t so the equation will be

13dtdx+(2x2−1)t3x(1−x2)=ax33x(1−x2)

after this the INTEGRATING FACTOR is

1x1−x2−−−−−√

But I am unable to SOLVE it FORWARD.

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3x(1-x^2)dy/dx+(2x^2-1)y^3=ax^3​

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3x(1-x^2)dy/dx+(2x^2-1)y^3=ax^3