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3t-2/4-2t+3/3=2/3-t with equation |
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Answer» LCM of the denominatos 3and 4 is 12 {3(3t-2)} - [4(2t+3)] /12=2/3-t 9t-6-8t-12=12(2/3-t) (solving BRACKETS) 9t-8t-18=24/3-12 t-18=8-12t t+12t = 8+18 13t=26 t=2 |
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