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| 1. |
3cotq=4 then find the value of 4 cosq- sinq/2 cosq + sinq |
| Answer» 3cotq=4 then cotq=4/3now, putting the value of cotq in a right angled triangle we get hypotenuse =5 [by pythagoras theorem] now find the value of cosq and sinq cosq=4/5 , sinq =3/5now putting this value n the equation we get, =>4*4/5-3/5//2*4/5+3/5 =>16/5-3/5//8/5+3/5 [multipling 4*4/5 in numerator and 2*4/5 in denomiator] =>13/5 //11/5=>13/5*5/11=>13/11 | |