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| 1. |
√3cosx+sinx=√2 solve |
| Answer» √3/2(cosx) +1/2(sinx)=1/√2=> cosπ/6•cosx + sinπ/4•sinx =1/√2=> cos(x-π/6)=cosπ/4=> x-π/6= 2nπ+_π/4=> x= 2nπ+π/6+-π/4 | |