3cos-1x = cos-1(4x3 - 3x), x ∈ [1/2, 1] – InterviewSolution

1.

3cos-1x = cos-1(4x3 - 3x), x ∈ [1/2, 1]

Answer»

माना cos^-1x = θ ∴ cosθ = x

∴ cos3θ = 4cos³θ – 3cos θ

⇒ cos3θ = 4x³ – 3x

⇒ 3θ = cos^-1(4x³ – 3x)

∴ 3cos^-1x = cos^-1(4x³ – 3x)

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