3b. The mole fraction He is 0.4 in gaseous mixture He and CH4. If both the gaseous are effusing throughthe constant area of the orifice of the container, thenwhat will be % composition by volume of CH4, gaseffusing out initially?A) 50% B) 40% C) 43% D) 75%

3b. The mole fraction He is 0.4 in gaseous mixture He and CH4. If bo

1.	3b. The mole fraction He is 0.4 in gaseous mixture He and CH4. If both the gaseous are effusing throughthe constant area of the orifice of the container, thenwhat will be % composition by volume of CH4, gaseffusing out initially?A) 50% B) 40% C) 43% D) 75%
Answer» POSITION by volume of CH4 gas EFFUSING out initially.Explanation: From the above calculation it is inferred that Helium diffuses at TWICE the rate of .As per the given condition, the mole fraction of helium is 0.40. To find the rate of diffusion assume 10 moles as total in which 4 mole He and 6 mole Moles of He that diffuse is twice the moles of .Thus 4 moles of He will diffuse in the same period of time as 3 moles or 4.0 liters of He will diffuse in the same period of time as 3.0 liters of .Percent by volume of = % volume Thus it is inferred that 42.8% of gas effuses out initially.Learn more about such conceptThe rates of diffusion of two gases A and B are in the ratio 1:4. If the ratio of their masses present inthe mixture is 2:3. The ratio of their mole fraction is: (9^1/3= 2.08) brainly.in/question/11908803Mole fraction of ethanol in ethanol water mixture is 0.25. Hence PERCENTAGE concentration of ethanol by weight of mixture is ? brainly.in/question/321544