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39. Find the smallest whole number by which the given number should be dividedto makeit aperfect Square number. 68.400OR |
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Answer» Answer: Step-by-step explanation: i) 252 = 2 x 2 x 3 x 3 x 7 Here, prime factor 7 has no pair. Therefore 252 MUST be DIVIDED by 7 to MAKE it a perfect square. \therefore252\div7=36∴252÷7=36 And \sqrt{36}=2\times3=6 36 =2×3=6(ii) 2925 = 3 x 3 x 5 x 5 x 13 Here, prime factor 13 has no pair. Therefore 2925 must be divided by 13 to make it a perfect square. \therefore2925\div13=225∴2925÷13=225 And \sqrt{225}=3\times5=15 225 =3×5=15 (iii) 396 = 2 x 2 x 3 x 3 x 11 Here, prime factor 11 has no pair. Therefore 396 must be divided by 11 to make it a perfect square. \therefore396\div11=36∴396÷11=36 And \sqrt{36}=2\times3=6 36 =2×3=6 ) 2645 = 5 x 23 x 23 Here, prime factor 5 has no pair. Therefore 2645 must be divided by 5 to make it a perfect square. \therefore2645\div5=529∴2645÷5=529 And \sqrt{529}=23 529 =23 v) 2800 = 2 x 2 x 2 x 2 x 5 x 5 x 7 Here, prime factor 7 has no pair. Therefore 2800 must be divided by 7 to make it a perfect square. \therefore2800\div7=400∴2800÷7=400 And \sqrt{400}=2\times2\times5=20 400 =2×2×5=20 vi) 1620 = 2 x 2 x 3 x 3 x 3 x 3 x 5 Here, prime factor 5 has no pair. Therefore 1620 must be divided by 5 to make it a perfect square. \therefore1620\div5=324∴1620÷5=324 And \sqrt{324}=2\times3\times3=18 324 =2×3×3=18 |
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