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39. Find the smallest whole number by which the given number should be dividedto make it aperfect Square number. 68.400OR |
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Answer» ONG>Answer: Step-by-step EXPLANATION: i) 252 = 2 x 2 x 3 x 3 x 7
Here, prime FACTOR 7 has no pair. THEREFORE 252 must be divided by 7 to make it a perfect square.
\therefore252\div7=36∴252÷7=36
And \sqrt{36}=2\times3=6 36 =2×3=6(ii) 2925 = 3 x 3 x 5 x 5 x 13
Here, prime factor 13 has no pair. Therefore 2925 must be divided by 13 to make it a perfect square.
\therefore2925\div13=225∴2925÷13=225
And \sqrt{225}=3\times5=15 225 =3×5=15 (iii) 396 = 2 x 2 x 3 x 3 x 11
Here, prime factor 11 has no pair. Therefore 396 must be divided by 11 to make it a perfect square.
\therefore396\div11=36∴396÷11=36
And \sqrt{36}=2\times3=6 36 =2×3=6 ) 2645 = 5 x 23 x 23
Here, prime factor 5 has no pair. Therefore 2645 must be divided by 5 to make it a perfect square.
\therefore2645\div5=529∴2645÷5=529
And \sqrt{529}=23 529 =23
v) 2800 = 2 x 2 x 2 x 2 x 5 x 5 x 7
Here, prime factor 7 has no pair. Therefore 2800 must be divided by 7 to make it a perfect square.
\therefore2800\div7=400∴2800÷7=400
And \sqrt{400}=2\times2\times5=20 400 =2×2×5=20
vi) 1620 = 2 x 2 x 3 x 3 x 3 x 3 x 5
Here, prime factor 5 has no pair. Therefore 1620 must be divided by 5 to make it a perfect square.
\therefore1620\div5=324∴1620÷5=324
And \sqrt{324}=2\times3\times3=18 324 =2×3×3=18
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