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38. A heap of wheat is in the form of a cone whose diameter is 48 m and height is 7m. Find itsvolume. If the heap is to be covered by canvas to protect it from rain, find the area of the canvasrequired.​

Answer»

\LARGE\underline\mathfrak{AnSwEr:}

•ᴠᴏʟᴜᴍᴇ ᴏғ ᴄᴏɴᴇ = \bf\ 4424cm^<klux>3</klux>

• ᴀʀᴇᴀ ᴏғ ᴄᴀɴᴠᴀs ʀᴇǫᴜɪʀᴇᴅ = \bf\ 1885.714cm^2

\LARGE\underline\mathfrak{Step \: by \: step \: explanation:}

\normalsize{\sf{\underline{\underline \orange{Given}}}}

• ᴅɪᴀᴍᴇᴛᴇʀ ᴏғ ᴄᴏɴᴇ = 48ᴄᴍ

•ʀᴀᴅɪᴜs ᴏғ ᴄᴏɴᴇ = \bf\frac{D}{2} \: = \: \frac{48}{2} \: = 24ᴄᴍ

• ʜᴇɪɢʜᴛ ᴏғ ᴄᴏɴᴇ = 7ᴄᴍ

•sʟᴀɴᴛ ʜᴇɪɢʜᴛ ᴏғ ᴄᴏɴᴇ(ʟ)=

\bf\displaystyle\sqrt{ h^2 \: + r^2} \: = \: \sqrt{49 \: + \: 576} \: = 25ᴄᴍ

\normalsize{\sf{\underline{\underline \orange{To \: find}}}}

•ᴠᴏʟᴜᴍᴇ ᴏғ ᴄᴏɴᴇ

• ᴀʀᴇᴀ ᴏғ ᴄᴀɴᴠᴀs ʀᴇǫᴜɪʀᴇᴅ

\normalsize{\sf{\underline{\underline \orange{Volume \: of \: cone}}}}

{\boxed{\bf\red{Volume \: of \: cone \: = \: \frac{1}{3} \pi r^2h}}}

ʙʟᴏᴄᴋ ᴛʜᴇ ᴠᴀʟᴜᴇs ɪɴ ᴀᴠᴀɪʟᴀʙʟᴇ ᴅᴀᴛᴀ ;

➠\large\tt\frac{1}{3} \times\frac{22}{7} \times\ (<klux>24</klux>)^2 \times\ 7

➠\large\tt\frac{ 1 \times\ 22 \times\  24 \times\ 24 \times\ 7}{ 3 \times\ 7}

➠\large\tt\ 1 \times\ 22 \times\ 8 \times\ 24

ᴄᴀɴᴄᴇʟ ᴛʜᴇ ᴠᴀʟᴜᴇs;( 24 ʙʏ 3 ᴀɴᴅ 7 ʙʏ 7)

➠\large\tt\ 4424cm^3

➠{\boxed{\sf{Volume \: of \: cone \: = \: 4424cm^{3} }}}

\normalsize{\sf{\underline{\underline \orange{Area \: of \: canvas \: required}}}}

•ᴀʀᴇᴀ ᴏғ ᴄᴀɴᴠᴀs ʀᴇǫᴜɪʀᴇᴅ ᴍᴇᴀɴs ᴛʜᴇ ᴏᴜᴛᴇʀ ᴄᴏᴠᴇʀɪɴɢ ʀᴇǫᴜɪʀᴇᴅ,sᴏ ᴡᴇ ᴜsᴇ ᴛʜᴇ ᴄᴜʀᴠᴇᴅ sᴜʀғᴀᴄᴇ ᴀʀᴇᴀ ғᴏʀᴍᴜʟᴀ

{\boxed{\bf\red{Curved \: surface \: area \: of \: cone \: = \: \pi rl}}}

ʙʟᴏᴄᴋ ᴛʜᴇ ᴠᴀʟᴜᴇs ɪᴍ ᴀᴠᴀɪʟᴀʙʟᴇ ᴅᴀᴛᴀ;

➠\large\tt\frac{22}{7} \times\ 24 \times\ 25

➠\large\tt\frac{ 22 \times\ 24 \times\ 25}{7}

➠\large\tt\ 1885.714cm^2

➠{\boxed{\sf{Area \: of \: canvas\: = \: 1885.714cm^2}}}



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