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38 & 39 both........

Answer»

VCeff= 10×20/20+10       =20/3μFSince, the capacitors are CONNECTED in series, charge will be same on both C1 AND C2Qeff= ceff×V       =20/3× 10⁻⁶×3×10³       =20×10⁻³       ==> 20000μC.39)The given CIRCUIT is in PARALLEL connection. So, potential through all the CAPACITOR s will be same the charge varies.So,Q₂=C₂ₓV     =6ₓ10⁻⁶ₓ90     =540μC



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