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37.85% and 92% alcoholic solutions are mixed to get 35 litres of an 89% alcoholic solution. How many litres of each solution are there in the new mixture ? (a) 10 L of the 1st, 25 L of the 2nd (b) 20 L of the 1st, 15 L of the 2nd (c) 15 L of the 1st, 20 L of the 2nd (d) None |
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Answer» (d) None Let x litres of the 37.85% alcoholic solution and (35 – x) litres of 92% alcoholic solution be required to get 35 L of 89% solution. Then, 37.85% of x + 92% of (35 – x) = 89% of 35 \(\Rightarrow\) \(\frac{37.85X}{100}\)+ \(\frac{92\times35}{100}\) - \(\frac{92\times X}{100}\) = \(\frac{89}{100}\) x 35 \(\Rightarrow\) 54.15x = 105 \(\Rightarrow\) x = \(\frac{105}{54.15}\) = 1.94 L (approx.) |
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