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36. A body released from the top of a tower of height h takes T seconds to reach the ground,The position of the body at T/4 seconds is​

Answer»

+ 1/2 × at^2U = 0 t = T/4S = 0×T/4 + 1/2 × 10 × (T/4)^2= 5 × T^2/16 POSITION of the BODY = H - 5T^2/16#Follow_me❤



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