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35. Prove that :cosec A +1(sec A + tan A)cosec A-1​

Answer»

Step-by-step EXPLANATION:

\frac{cosec \: a+ 1}{cosec \: a - 1}  =  \frac{cosec \: a + 1}{cosec \: a - 1}  \times  \frac{cosec \: a + 1}{cosec \: a  + 1}

=  \frac{ {(cosec \: a + 1)}^{2} }{ {cosec }^{2} a - 1}

=  \frac{ {(cosec \: a \: + 1)}^{2} }{ {cot}^{2} a}

=   { (\frac{cosec \: a + 1}{cot \: a} )}^{2}

=  { (\frac{cosec \: a}{cot \: a}  +  \frac{1}{cot \: a} )}^{2}

= { (\frac{ \frac{1}{sin \: a} }{ \frac{cos \: a}{sin \: a} } + tan \: a) }^{2}

=  { (\frac{1}{cos \: a}  + tan \: a)}^{2}

=  {(sec \: a \:  +  \: tan \: a)}^{2}



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