34. Two numbers'a' and 'W are selected sucessively witbonut replacemen

1.	34. Two numbers'a' and 'W are selected sucessively witbonut replacementin o. Anelemdefiritifrom the integers 1 to 10, The probability that i is an integn,17(di
Answer» The total number of possibilities is 10∗9 = 90 since we are choosing two numbers without replacement and order matters. Hence the cases are (2,1),(3,1),(4,1),(5,1),(6,1),(7,1),(8,1),(9,1)and(10,1) (4,2),(6,2),(8,2),(10,2) (6,3),(9,3) (8,4) (10,5) For all b greater than 5 the smallest multiple is greater than 10.Hence they dont contribute to the total. Hence a total of 9+4+2+1+1=17 valid possibilities. Hence the probability is 17/90

34. Two numbers'a' and 'W are selected sucessively witbonut replacementin o. Anelemdefiritifrom the integers 1 to 10, The probability that i is an integn,17(di

Answer»

The total number of possibilities is 10∗9 = 90 since we are choosing two numbers without replacement and order matters.

Hence the cases are

(2,1),(3,1),(4,1),(5,1),(6,1),(7,1),(8,1),(9,1)and(10,1)

(4,2),(6,2),(8,2),(10,2)

(6,3),(9,3)

(8,4)

(10,5)

For all b greater than 5 the smallest multiple is greater than 10.Hence they dont contribute to the total.

Hence a total of 9+4+2+1+1=17 valid possibilities.

Hence the probability is 17/90