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34. If 3 tan 20 = 3 and 0°< 0 S 90°. Find the value of 3V3 cos e + 2Sine - 6tan²0OR

Answer»

Given,root(3)tan 2theta = 3

tan 2theta = 3/root(3) = root(3)tan 2theta = tan 60theta = 60/2 = 30

Therefore,3root(3) cos theta + 2sin theta - 6 tan^2 theta

= 3root(3) cos 30 + 2sin 30 - 6 tan^2 30

= 3root(3)*root(3) + 2*1/root(2) - 6*(1/root(3))^2

= 3*3 + root(2) - 6/3

= 9 - 2 + root(2)

= 7 + root(2)



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