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34.A clock has copper pendulum beats seconds correctly when temperature of the room is 30°C, the time loss or gain per day when temperature falls to 10°C is (α=1.9×10 ￣⁵K￣¹).loss 16.43 secloss 4.2 sec.gain 17.28 secgain 4.2 sec

Answer»

Given:

Temperature at which the clock PENDULUM BEATS seconds correctly = 30°C

α = 1.9 × 10⁻⁵K⁻¹

To find:

Time loss or gain per day when temperature falls to 10°C

Solution:

Let us assume that the pendulum has a time period of 2 sec.

ΔT = 1/2*αΔθt

Where Δθ = 10°-30°C =  -20°C

t = Seconds in a day = 24×60×60

Putting the values in the EQUATION we get:

ΔT = 1/2×1.9 × 10⁻⁵×(-20)×24×60×60

ΔT = -16.416

Here NEGATIVE sign shows that time is lost.

∴ Time lost in one day = 16.416 sec

Therefore time lost in one day will be EQUAL to 16.416 sec.


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