1.

(3३ न 29 - 5P + (3x — 4y + 1P =0

Answer»

(3x + 2y - 5)^2 + (3x - 4y + 1)^2=09x^2 + 4y^2 +25 +12xy -20y -30x +9x^2 +16y^2 + 1 -24xy -8y -6x=018x^2 +20y^2-12xy -36x -28y+26=0

sum of the squares are zero so they are individually 0



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