33. In triangle ABC,segAB = SegA C & P is any points on AC.Through C, a line is drawn to intersect BP produced in Q such that ANGLE ABQ=ANGLE ACQ .Prove that ANGLE AQC=90^° +1/2 ANGLE BAC.

33. In triangle ABC,segAB = SegA C & P is any points on AC.Through C,

1.	33. In triangle ABC,segAB = SegA C & P is any points on AC.Through C, a line is drawn to intersect BP produced in Q such that ANGLE ABQ=ANGLE ACQ .Prove that ANGLE AQC=90^° +1/2 ANGLE BAC.
Answer» 33. In triangle ABC,segAB = SegA C & P is any points on AC.Through C, a line is drawn to intersect BP produced in Q such that ANGLE ABQ=ANGLE ACQ .Prove that ANGLE AQC=90^° +1/2 ANGLE BAC.