(33/8)*(quad*text)

1.	(33/8)(quadtext)
Answer» We know that for collinear points, the area of the triangle formed by them is 0. Therefore, Area of triangle = 1/2(x1(y2- y3) + x2(y3-y1) + x3(y1-y2) = 0 Here, x1 = - 2, x2 = k, x3 = 5y1 = - 3, y2 = 4, y3 = 5 Hence,1/2(-2(4-5) + k(5-(-3)) + 5(-3-4)) = 0 -2(-1) + k(8) + 5(-7) = 0 2 + 8k - 35 = 0 8k - 33 = 0 k = 33/8 Therefore the value of k = 33/8 (b) is correct option.

(33/8)(quadtext)

Answer»

We know that for collinear points, the area of the triangle formed by them is 0.

Therefore, Area of triangle = 1/2(x1(y2- y3) + x2(y3-y1) + x3(y1-y2) = 0

Here, x1 = - 2, x2 = k, x3 = 5y1 = - 3, y2 = 4, y3 = 5

Hence,1/2(-2(4-5) + k(5-(-3)) + 5(-3-4)) = 0

-2(-1) + k(8) + 5(-7) = 0

2 + 8k - 35 = 0

8k - 33 = 0

k = 33/8

Therefore the value of k = 33/8

(b) is correct option.