310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from `25^(@)C` to `35^(@)C`. The amount of heat required to raise the temperature of the gas through the same range at constant volume, isA. 384 JB. 144 JC. 276 JD. 452 J

310 J of heat is required to rise the temperature of 2 moles of an ide

1.	310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from `25^(@)C` to `35^(@)C`. The amount of heat required to raise the temperature of the gas through the same range at constant volume, isA. 384 JB. 144 JC. 276 JD. 452 J
Answer» Correct Answer - B At constant pressure, Heat required `=nC_(p)DeltaT` `rArr" " 310=2xxC_(p)xx(35-25)` `rArr" " C_(p)=(310)/(20)=15.5J "mol" ^(-1)K^(-1)` Similarly ,at constant volume , Heat required `nC_(v)DeltaT` `=2(C_(p)-R)xx(35-25)" " [becauseC_(p)-C_(v)=R] ` `=2xx(15.5-8.3)xx10` `=2xx7.2xx10=144 J`

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310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from `25^(@)C` to `35^(@)C`. The amount of heat required to raise the temperature of the gas through the same range at constant volume, isA. 384 JB. 144 JC. 276 JD. 452 J

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