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31. Find the limits of real value of x so that the expression5x2 +63-8 is non-negative. |
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Answer» 5x^2 + 6x - 8 >= 05x^2 + 10x - 4x - 8 >= 05x(x + 2) - 4(x + 2) >= 0(5x - 4)(x + 2) >= 0 x >= 4/5, x >= - 2 or x <= 2 Therefore, Limit of real value of x is(-infinity, 2) U (4/5, infinity) |
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