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30g of ice at 0°c is mixed with 50g of water at 10°c. Then find its resultant Temp. |
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Answer» 0°C has a total latent heat ofQ=m*L = 540*80 = 43200 cal.Now for water to come at 0°C and it's state to REMAIN as water, we need to remove heat from it which is given by,Q= m*Cp*(∆T) = 540* 1* 80 = 43200 cal.So, we can see thatHeat released by water to reach from 80°C to 0°C = heat REQUIRED by ICE to melt into water at 0°C.So, the ice will melt to water and it's temperature will be 0°C.Hence, the final state would be water at 0°C.So, the answer is A.Hope this help you. |
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