30 mL of a solution containing 9.15 gm L−1 of an oxalate KxHy(C2O4)z – InterviewSolution

1.	30 mL of a solution containing 9.15 gm L−1 of an oxalate KxHy(C2O4)z.nH2O are required for titrating 27 mL of 0.12 N NaOH and 36 mL of 0.12 M KMnO4 separately. The value of x+y+z is:
Answer» $30 m L$ of a solution containing $9.15 g m L^{- 1}$ of an oxalate $K_{x} H_{y} (C_{2} O_{4})_{z} . n H_{2} O$ are required for titrating $27 m L$ of $0.12 N N a O H$ and $36 m L$ of $0.12 M K M n O_{4}$ separately. The value of $x + y + z$ is:

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