30 ml of 0.06 M solution of the protonated form of an anion of acid me – InterviewSolution

1.	30 ml of 0.06 M solution of the protonated form of an anion of acid methonine (H_2A^(+)) is treated with 0.09 M NaOH. Calculate pH after addition of 20 ml of base pKa_1=2.28 and pKa_2=9.2
Answer» 5.5 5.74 9.5 None Solution :`PH=(pK_(a_1)+pK_(a_2))/2 =(2.28+9.2)/2=5.74`

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