Saved Bookmarks
| 1. |
30. Consider the following frequency distribution of manual workersFrequency10Expenditure (in Rs.)0-500500-10001000-15001500-20002000-2500131015811Then, find the average expenditure which is done by the maximum number of manuaal workers |
|
Answer» Answer: ANSWER We observe that the class 1500−2000 has the MAXIMUM frequency 40. So, 1500−2000 is a MODAL class. l=1500,h=2000−1500=500,f=40,f 1
=24 and f 2
=33 ⇒ Mode=l+ 2f−f 1
−f 2
f−f 1
×h =1500+ 2×40−24−33 40−24
×500 =1500+ 80−57 16
×500 =1500+ 23 16
×500 =1500+347.826 =1847.826 |
|