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\( 3 x^{2}+10 x-25=0 \) |
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Answer» Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula. \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) 3x2 + 10x - 25 = 0 a = 3 b = 10 c = -25 \(x = {-10 \pm \sqrt{10^2-4\times3(-25)} \over 2\times3}\) \(x = \frac{-10\pm20}{6}\) \(x = \frac{-10+20}{6}; \frac{-10-20}{6}\) \(x = \frac{5}{3}, -5\) |
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