1.

√3 sin theta -cos theta =0 then 2 tan theta /1-tan^2 theta

Answer»

Answer:

from given,(3)^1/2 sin theta=cos theta

TAN theta=1/(3)^1/2

theta=30°

THEREFORE, 2tan theta/1-tan^2 theta

=2/(3)^1/3/1-1/3

=2/(3)^1/2/2/3

=(3)^1/2

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