3 \operatorname { log } 4 - 2 \operatorname { log } 6 + \operatorname

1.	3 \operatorname { log } 4 - 2 \operatorname { log } 6 + \operatorname { log } ( 18 ) ^ { 3 / 2 }
Answer» 3log4 - 2log6 +log(18)^(3/2) = log(4)³ - log6² + log(18)^3/2)= log[(64×18^(3/2))/36)]= log[16×2×√18)= log[32] + log[√18]= 5log2 + 1/2log18= 5log2 + 1/2log[332]=5log2 + 1/2[2log3+log2]= 11/2*log[2] + log[3]

3 \operatorname { log } 4 - 2 \operatorname { log } 6 + \operatorname { log } ( 18 ) ^ { 3 / 2 }

Answer»

3log4 - 2log6 +log(18)^(3/2)

= log(4)³ - log6² + log(18)^3/2)= log[(64×18^(3/2))/36)]= log[16×2×√18)= log[32] + log[√18]= 5log2 + 1/2log18= 5log2 + 1/2log[3*3*2]=5log2 + 1/2[2log3+log2]= 11/2*log[2] + log[3]

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3 \operatorname { log } 4 - 2 \operatorname { log } 6 + \operatorname { log } ( 18 ) ^ { 3 / 2 }

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