3 moles of a gas mixture having 8.3 m3 volume and temperature of 90.5 K is compressed to 1/5th of the initial volume. The change in its adiabatic compressibility, if the gas obeys PV19/13= constant is −x×10−3 Pa−1 [R=8.3 J/mol-K and 15γ−1=−0.905], then x is

3 moles of a gas mixture having 8.3 m3 volume and temperature of 90.5

1.	3 moles of a gas mixture having 8.3 m3 volume and temperature of 90.5 K is compressed to 1/5th of the initial volume. The change in its adiabatic compressibility, if the gas obeys PV19/13= constant is −x×10−3 Pa−1 [R=8.3 J/mol-K and 15γ−1=−0.905], then x is
Answer» 3 moles of a gas mixture having $8.3 m^{3}$ volume and temperature of $90.5 K$ is compressed to $1 / 5^{t h}$ of the initial volume. The change in its adiabatic compressibility, if the gas obeys $P V^{19 / 13} =$ constant is $- x \times 10^{- 3} P a^{- 1}$ [ $R = 8.3$ J/mol-K and $\frac{1}{5^{γ}} - 1 = - 0.905$ ], then $x$ is

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3 moles of a gas mixture having 8.3 m3 volume and temperature of 90.5 K is compressed to 1/5th of the initial volume. The change in its adiabatic compressibility, if the gas obeys PV19/13= constant is −x×10−3 Pa−1 [R=8.3 J/mol-K and 15γ−1=−0.905], then x is

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